[WIP] Before refactor the compute)_chunked_prefill.
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@@ -6,9 +6,10 @@ Test: XAttention Triton kernels
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2. softmax_fuse_block_sum: 对 attention scores 做 softmax 后按 block 求和
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数据流:
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Q, K [batch, heads, seq_len, head_dim]
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Q [batch, heads, q_len, head_dim]
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K [batch, heads, kv_len, head_dim]
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↓ flat_group_gemm_fuse_reshape
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attn_scores [batch, heads, seq_len/stride, seq_len/stride]
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attn_scores [batch, heads, q_len/stride, kv_len/stride]
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↓ softmax_fuse_block_sum
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block_sums [batch, heads, q_blocks, k_blocks]
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"""
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@@ -21,7 +22,11 @@ from nanovllm.ops.xattn import flat_group_gemm_fuse_reshape, softmax_fuse_block_
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# 参数配置
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# ============================================================
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seq_len = 512 # Triton 要求 seq_len >= stride * BLOCK_M = 4 * 128 = 512
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# Triton 约束: q_len >= stride * BLOCK_M, kv_len >= stride * BLOCK_N
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# A100: BLOCK_M = BLOCK_N = 128, 所以 min = 4 * 128 = 512
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# RTX 3090: BLOCK_M = BLOCK_N = 64, 所以 min = 4 * 64 = 256
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q_len = 512
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kv_len = 2048
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head_dim = 128
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stride = 4
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block_size = 128 # softmax block size (in reshaped space)
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@@ -31,26 +36,56 @@ segment_size = 128 # Triton kernel 要求 segment_size >= block_size
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# 构造输入: 偶数位置=1, 奇数位置=2
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# ============================================================
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Q = torch.zeros(1, 1, seq_len, head_dim, dtype=torch.bfloat16).cuda()
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K = torch.zeros(1, 1, seq_len, head_dim, dtype=torch.bfloat16).cuda()
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for i in range(seq_len):
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Q = torch.zeros(1, 1, q_len, head_dim, dtype=torch.bfloat16).cuda()
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K = torch.zeros(1, 1, kv_len, head_dim, dtype=torch.bfloat16).cuda()
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for i in range(q_len):
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if i % 2 == 0:
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Q[0, 0, i, :] = 1
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K[0, 0, i, :] = 1
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else:
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Q[0, 0, i, :] = 2
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for i in range(kv_len):
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if i % 2 == 0:
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K[0, 0, i, :] = 1
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else:
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K[0, 0, i, :] = 2
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# ============================================================
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# Step 1: flat_group_gemm_fuse_reshape
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# Step 1: flat_group_gemm_fuse_reshape (chunked along K)
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# ============================================================
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attn_scores = flat_group_gemm_fuse_reshape(
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Q, K, stride,
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chunk_start=0,
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chunk_end=seq_len // stride,
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is_causal=False
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)
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q_reshaped_len = q_len // stride # 128
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kv_reshaped_len = kv_len // stride # 512
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# 将 K 沿着长度维度分成多个 chunk
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k_chunk_size = 512 # 每个 chunk 512 tokens
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num_k_chunks = kv_len // k_chunk_size # 4 chunks
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attn_scores_list = []
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for k_chunk_idx in range(num_k_chunks):
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k_start = k_chunk_idx * k_chunk_size
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k_end = k_start + k_chunk_size
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K_chunk = K[:, :, k_start:k_end, :] # [1, 1, k_chunk_size, head_dim]
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# 对每个 K chunk 调用 flat_group_gemm_fuse_reshape
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# 输出: [batch, heads, q_len/stride, k_chunk_size/stride]
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attn_chunk = flat_group_gemm_fuse_reshape(
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Q, K_chunk, stride,
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chunk_start=0,
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chunk_end=q_reshaped_len,
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is_causal=False
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)
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attn_scores_list.append(attn_chunk)
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# 拼接所有 K chunks 的结果
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# 每个 chunk: [1, 1, q_reshaped_len, k_chunk_size/stride]
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# 拼接后: [1, 1, q_reshaped_len, kv_reshaped_len]
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attn_scores = torch.cat(attn_scores_list, dim=-1)
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# 验证 shape: [batch, heads, q_len/stride, kv_len/stride]
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assert attn_scores.shape == (1, 1, q_reshaped_len, kv_reshaped_len), \
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f"shape mismatch: {attn_scores.shape} != (1, 1, {q_reshaped_len}, {kv_reshaped_len})"
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# 验证: 反对角线求和
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# 每个 stride x stride 块的反对角线: Q[奇]*K[偶] + Q[偶]*K[奇] = 2*1 + 1*2 = 4
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@@ -63,7 +98,6 @@ assert actual_gemm == expected_gemm, f"flat_group_gemm: {actual_gemm} != {expect
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# Step 2: softmax_fuse_block_sum
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# ============================================================
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reshaped_len = seq_len // stride
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scale = 1.4426950408889634 # log2(e) for exp2
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block_sums = softmax_fuse_block_sum(
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@@ -71,15 +105,24 @@ block_sums = softmax_fuse_block_sum(
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block_size,
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segment_size,
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chunk_start=0,
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chunk_end=reshaped_len,
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real_q_len=reshaped_len,
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chunk_end=q_reshaped_len,
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real_q_len=q_reshaped_len,
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scale=scale,
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is_causal=False
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)
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# 验证 shape: [batch, heads, q_blocks, k_blocks]
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q_blocks = q_reshaped_len // block_size # 128 / 128 = 1
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k_blocks = kv_reshaped_len // block_size # 512 / 128 = 4
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assert block_sums.shape == (1, 1, q_blocks, k_blocks), \
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f"shape mismatch: {block_sums.shape} != (1, 1, {q_blocks}, {k_blocks})"
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# 验证: 每个 block 的 softmax 结果求和
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# 所有 attn_scores 相同 → softmax 均匀分布 → block_sum = block_size^2 / reshaped_len
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expected_sum = block_size * block_size / reshaped_len
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# 所有 attn_scores 相同 → softmax 均匀分布
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# 每行对一个 K block 的贡献 = block_size / kv_reshaped_len
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# 每个 Q block 有 block_size 行
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# block_sum = block_size * (block_size / kv_reshaped_len)
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expected_sum = block_size * block_size / kv_reshaped_len
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actual_sum = block_sums[0, 0, 0, 0].item()
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assert actual_sum == expected_sum, f"softmax_fuse_block_sum: {actual_sum} != {expected_sum}"
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